MCQ TEST - CLASS 10 MATHS -

#1. Define Fundamental theorem of Arithmetic

Every coprime number can be factorized as a product of primes, and this factorization is unique, apart from the order in which the prime factors occur.

Every composite number can be factorized as a product of primes, and this factorization is not unique, apart from the order in which the prime factors occur.

Every composite number can be factorized as a product of primes, and this factorization is unique, apart from the order in which the prime factors occur.

Every composite number can be factorized as a product of coprimes, and this factorization is unique, apart from the order in which the prime factors occur.

#2. HCF of 8, 9, 25 is

9

1

25

8

#3. Which of the following is not irrational?

(√2 -√3)(√2 + √3)

(2 – √3)2

(√2 + √3)2

2√7 / 7 or 2√7 ÷ 7

#4. The product of a rational and irrational number is

none of the above

irrational

rational

both of the above

#5. The sum of a rational and irrational number is

irrational

both of the above

none of the above

rational

#6. The product of two different irrational numbers is always

irrational

rational

both of the above

none of the above

#7. The sum of two irrational numbers is always

rational

rational or irrational

one

irrational

#8. If b = 3, then any integer can be expressed as a =

3q

3q, 3q+ 1, 3q + 2

3q+1

none of the above

#9. The product of three consecutive positive integers is divisible by

4

only 1

no common factor

6

#10. The decimal form of 129 / 2² 5⁷ 7⁵ is

non-terminating

none of these

terminating

non-terminating non-repeating

CLASS 10 MATHS CH1

Real Numbers

Results

#1. Define Fundamental theorem of Arithmetic

#2. HCF of 8, 9, 25 is

#3. Which of the following is not irrational?

#4. The product of a rational and irrational number is

#5. The sum of a rational and irrational number is

#6. The product of two different irrational numbers is always

#7. The sum of two irrational numbers is always

#8. If b = 3, then any integer can be expressed as a =

#9. The product of three consecutive positive integers is divisible by

#10. The decimal form of 129 / 2² 5⁷ 7⁵ is